Cldr.Calendar.Interval.year
You're seeing just the function
year
, go back to Cldr.Calendar.Interval module for more information.
Specs
year(Date.t()) :: Date.Range.t()
Returns a Date.Range.t
that represents
the year
.
The range is enumerable.
Arguments
year
is anyyear
forcalendar
calendar
is any module that implements theCalendar
andCldr.Calendar
behaviours. The default isCldr.Calendar.Gregorian
.
Returns
- A
Date.Range.t()
representing the the enumerable days in theyear
Examples
iex> Cldr.Calendar.Interval.year 2019, Cldr.Calendar.Fiscal.UK
#DateRange<~D[2019-01-01 Cldr.Calendar.Fiscal.UK], ~D[2019-12-31 Cldr.Calendar.Fiscal.UK]>
iex> Cldr.Calendar.Interval.year 2019, Cldr.Calendar.NRF
#DateRange<~D[2019-W01-1 Cldr.Calendar.NRF], ~D[2019-W52-7 Cldr.Calendar.NRF]>
Specs
year(Calendar.year(), Cldr.Calendar.calendar()) :: Date.Range.t()