Cldr.Calendar.Interval.year

You're seeing just the function year, go back to Cldr.Calendar.Interval module for more information.

year(date)

Specs

year(Date.t()) :: Date.Range.t()

Returns a Date.Range.t that represents the year.

The range is enumerable.

Arguments

year is any year for calendar
calendar is any module that implements the Calendar and Cldr.Calendar behaviours. The default is Cldr.Calendar.Gregorian.

Returns

A Date.Range.t() representing the the enumerable days in the year

Examples

iex> Cldr.Calendar.Interval.year 2019, Cldr.Calendar.Fiscal.UK
#DateRange<~D[2019-01-01 Cldr.Calendar.Fiscal.UK], ~D[2019-12-31 Cldr.Calendar.Fiscal.UK]>

iex> Cldr.Calendar.Interval.year 2019, Cldr.Calendar.NRF
#DateRange<~D[2019-W01-1 Cldr.Calendar.NRF], ~D[2019-W52-7 Cldr.Calendar.NRF]>

year(year, calendar \\ Cldr.Calendar.Gregorian)

Specs

year(Calendar.year(), Cldr.Calendar.calendar()) :: Date.Range.t()