Elixir v1.6.6 Enum View Source

Provides a set of algorithms that enumerate over enumerables according to the Enumerable protocol.

iex> Enum.map([1, 2, 3], fn(x) -> x * 2 end)
[2, 4, 6]

Some particular types, like maps, yield a specific format on enumeration. For example, the argument is always a {key, value} tuple for maps:

iex> map = %{a: 1, b: 2}
iex> Enum.map(map, fn {k, v} -> {k, v * 2} end)
[a: 2, b: 4]

Note that the functions in the Enum module are eager: they always start the enumeration of the given enumerable. The Stream module allows lazy enumeration of enumerables and provides infinite streams.

Since the majority of the functions in Enum enumerate the whole enumerable and return a list as result, infinite streams need to be carefully used with such functions, as they can potentially run forever. For example:

Enum.each Stream.cycle([1, 2, 3]), &IO.puts(&1)

Link to this section Summary

Functions

Returns true if the given fun evaluates to true on all of the items in the enumerable

Returns true if the given fun evaluates to true on any of the items in the enumerable

Finds the element at the given index (zero-based)

Splits enumerable on every element for which fun returns a new value

Shortcut to chunk_every(enumerable, count, count)

Returns list of lists containing count items each, where each new chunk starts step elements into the enumerable

Chunks the enumerable with fine grained control when every chunk is emitted

Given an enumerable of enumerables, concatenates the enumerables into a single list

Concatenates the enumerable on the right with the enumerable on the left

Returns the size of the enumerable

Returns the count of items in the enumerable for which fun returns a truthy value

Enumerates the enumerable, returning a list where all consecutive duplicated elements are collapsed to a single element

Enumerates the enumerable, returning a list where all consecutive duplicated elements are collapsed to a single element

Drops the amount of items from the enumerable

Returns a list of every nth item in the enumerable dropped, starting with the first element

Drops items at the beginning of the enumerable while fun returns a truthy value

Invokes the given fun for each item in the enumerable

Determines if the enumerable is empty

Finds the element at the given index (zero-based)

Finds the element at the given index (zero-based)

Filters the enumerable, i.e. returns only those elements for which fun returns a truthy value

Returns the first item for which fun returns a truthy value. If no such item is found, returns default

Similar to find/3, but returns the index (zero-based) of the element instead of the element itself

Similar to find/3, but returns the value of the function invocation instead of the element itself

Maps the given fun over enumerable and flattens the result

Maps and reduces an enumerable, flattening the given results (only one level deep)

Splits the enumerable into groups based on key_fun

Intersperses element between each element of the enumeration

Inserts the given enumerable into a collectable

Inserts the given enumerable into a collectable according to the transformation function

Joins the given enumerable into a binary using joiner as a separator

Returns a list where each item is the result of invoking fun on each corresponding item of enumerable

Returns a list of results of invoking fun on every nth item of enumerable, starting with the first element

Maps and joins the given enumerable in one pass

Invokes the given function to each item in the enumerable to reduce it to a single element, while keeping an accumulator

Returns the maximal element in the enumerable according to Erlang’s term ordering

Returns the maximal element in the enumerable as calculated by the given function

Checks if element exists within the enumerable

Returns the minimal element in the enumerable according to Erlang’s term ordering

Returns the minimal element in the enumerable as calculated by the given function

Returns a tuple with the minimal and the maximal elements in the enumerable according to Erlang’s term ordering

Returns a tuple with the minimal and the maximal elements in the enumerable as calculated by the given function

Returns a random element of an enumerable

Invokes fun for each element in the enumerable with the accumulator

Invokes fun for each element in the enumerable with the accumulator

Reduces the enumerable until fun returns {:halt, term}

Returns elements of enumerable for which the function fun returns false or nil

Returns a list of elements in enumerable in reverse order

Reverses the elements in enumerable, appends the tail, and returns it as a list

Reverses the enumerable in the range from initial position start through count elements

Applies the given function to each element in the enumerable, storing the result in a list and passing it as the accumulator for the next computation. Uses the first element in the enumerable as the starting value

Applies the given function to each element in the enumerable, storing the result in a list and passing it as the accumulator for the next computation. Uses the given acc as the starting value

Returns a list with the elements of enumerable shuffled

Returns a subset list of the given enumerable, from range.first to range.last positions

Returns a subset list of the given enumerable, from start position with amount of elements if available

Sorts the enumerable according to Erlang’s term ordering

Sorts the enumerable by the given function

Sorts the mapped results of the enumerable according to the provided sorter function

Splits the enumerable into two enumerables, leaving count elements in the first one

Splits enumerable in two at the position of the element for which fun returns false for the first time

Splits the enumerable in two lists according to the given function fun

Returns the sum of all elements

Takes the first amount items from the enumerable

Returns a list of every nth item in the enumerable, starting with the first element

Takes count random items from enumerable

Takes the items from the beginning of the enumerable while fun returns a truthy value

Converts enumerable to a list

Enumerates the enumerable, removing all duplicated elements

Enumerates the enumerable, by removing the elements for which function fun returned duplicate items

Opposite of Enum.zip/2; extracts a two-element tuples from the enumerable and groups them together

Returns the enumerable with each element wrapped in a tuple alongside its index

Zips corresponding elements from a finite collection of enumerables into one list of tuples

Zips corresponding elements from two enumerables into one list of tuples

Link to this section Types

Link to this section Functions

Link to this function all?(enumerable, fun \\ fn x -> x end) View Source
all?(t(), (element() -> as_boolean(term()))) :: boolean()

Returns true if the given fun evaluates to true on all of the items in the enumerable.

It stops the iteration at the first invocation that returns false or nil.

Examples

iex> Enum.all?([2, 4, 6], fn(x) -> rem(x, 2) == 0 end)
true

iex> Enum.all?([2, 3, 4], fn(x) -> rem(x, 2) == 0 end)
false

If no function is given, it defaults to checking if all items in the enumerable are truthy values.

iex> Enum.all?([1, 2, 3])
true

iex> Enum.all?([1, nil, 3])
false
Link to this function any?(enumerable, fun \\ fn x -> x end) View Source
any?(t(), (element() -> as_boolean(term()))) :: boolean()

Returns true if the given fun evaluates to true on any of the items in the enumerable.

It stops the iteration at the first invocation that returns a truthy value (not false or nil).

Examples

iex> Enum.any?([2, 4, 6], fn(x) -> rem(x, 2) == 1 end)
false

iex> Enum.any?([2, 3, 4], fn(x) -> rem(x, 2) == 1 end)
true

If no function is given, it defaults to checking if at least one item in the enumerable is a truthy value.

iex> Enum.any?([false, false, false])
false

iex> Enum.any?([false, true, false])
true
Link to this function at(enumerable, index, default \\ nil) View Source
at(t(), index(), default()) :: element() | default()

Finds the element at the given index (zero-based).

Returns default if index is out of bounds.

A negative index can be passed, which means the enumerable is enumerated once and the index is counted from the end (e.g. -1 finds the last element).

Note this operation takes linear time. In order to access the element at index index, it will need to traverse index previous elements.

Examples

iex> Enum.at([2, 4, 6], 0)
2

iex> Enum.at([2, 4, 6], 2)
6

iex> Enum.at([2, 4, 6], 4)
nil

iex> Enum.at([2, 4, 6], 4, :none)
:none
Link to this function chunk_by(enumerable, fun) View Source
chunk_by(t(), (element() -> any())) :: [list()]

Splits enumerable on every element for which fun returns a new value.

Returns a list of lists.

Examples

iex> Enum.chunk_by([1, 2, 2, 3, 4, 4, 6, 7, 7], &(rem(&1, 2) == 1))
[[1], [2, 2], [3], [4, 4, 6], [7, 7]]
Link to this function chunk_every(enumerable, count) View Source
chunk_every(t(), pos_integer()) :: [list()]

Shortcut to chunk_every(enumerable, count, count).

Link to this function chunk_every(enumerable, count, step, leftover \\ []) View Source
chunk_every(t(), pos_integer(), pos_integer(), t() | :discard) :: [list()]

Returns list of lists containing count items each, where each new chunk starts step elements into the enumerable.

step is optional and, if not passed, defaults to count, i.e. chunks do not overlap.

If the last chunk does not have count elements to fill the chunk, elements are taken from leftover to fill in the chunk. If leftover does not have enough elements to fill the chunk, then a partial chunk is returned with less than count elements.

If :discard is given in leftover, the last chunk is discarded unless it has exactly count elements.

Examples

iex> Enum.chunk_every([1, 2, 3, 4, 5, 6], 2)
[[1, 2], [3, 4], [5, 6]]

iex> Enum.chunk_every([1, 2, 3, 4, 5, 6], 3, 2, :discard)
[[1, 2, 3], [3, 4, 5]]

iex> Enum.chunk_every([1, 2, 3, 4, 5, 6], 3, 2, [7])
[[1, 2, 3], [3, 4, 5], [5, 6, 7]]

iex> Enum.chunk_every([1, 2, 3, 4], 3, 3, [])
[[1, 2, 3], [4]]

iex> Enum.chunk_every([1, 2, 3, 4], 10)
[[1, 2, 3, 4]]

iex> Enum.chunk_every([1, 2, 3, 4, 5], 2, 3, [])
[[1, 2], [4, 5]]
Link to this function chunk_while(enumerable, acc, chunk_fun, after_fun) View Source
chunk_while(
  t(),
  acc(),
  (element(), acc() ->
     {:cont, chunk, acc()} | {:cont, acc()} | {:halt, acc()}),
  (acc() -> {:cont, chunk, acc()} | {:cont, acc()})
) :: Enumerable.t()
when chunk: any()

Chunks the enumerable with fine grained control when every chunk is emitted.

chunk_fun receives the current element and the accumulator and must return {:cont, element, acc} to emit the given chunk and continue with accumulator or {:cont, acc} to not emit any chunk and continue with the return accumulator.

after_fun is invoked when iteration is done and must also return {:cont, element, acc} or {:cont, acc}.

Returns a list of lists.

Examples

iex> chunk_fun = fn i, acc ->
...>   if rem(i, 2) == 0 do
...>     {:cont, Enum.reverse([i | acc]), []}
...>   else
...>     {:cont, [i | acc]}
...>   end
...> end
iex> after_fun = fn
...>   [] -> {:cont, []}
...>   acc -> {:cont, Enum.reverse(acc), []}
...> end
iex> Enum.chunk_while(1..10, [], chunk_fun, after_fun)
[[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]]
Link to this function concat(enumerables) View Source
concat(t()) :: t()

Given an enumerable of enumerables, concatenates the enumerables into a single list.

Examples

iex> Enum.concat([1..3, 4..6, 7..9])
[1, 2, 3, 4, 5, 6, 7, 8, 9]

iex> Enum.concat([[1, [2], 3], [4], [5, 6]])
[1, [2], 3, 4, 5, 6]
Link to this function concat(left, right) View Source
concat(t(), t()) :: t()

Concatenates the enumerable on the right with the enumerable on the left.

This function produces the same result as the Kernel.++/2 operator for lists.

Examples

iex> Enum.concat(1..3, 4..6)
[1, 2, 3, 4, 5, 6]

iex> Enum.concat([1, 2, 3], [4, 5, 6])
[1, 2, 3, 4, 5, 6]

Returns the size of the enumerable.

Examples

iex> Enum.count([1, 2, 3])
3
Link to this function count(enumerable, fun) View Source
count(t(), (element() -> as_boolean(term()))) :: non_neg_integer()

Returns the count of items in the enumerable for which fun returns a truthy value.

Examples

iex> Enum.count([1, 2, 3, 4, 5], fn(x) -> rem(x, 2) == 0 end)
2
Link to this function dedup(enumerable) View Source
dedup(t()) :: list()

Enumerates the enumerable, returning a list where all consecutive duplicated elements are collapsed to a single element.

Elements are compared using ===.

If you want to remove all duplicated elements, regardless of order, see uniq/1.

Examples

iex> Enum.dedup([1, 2, 3, 3, 2, 1])
[1, 2, 3, 2, 1]

iex> Enum.dedup([1, 1, 2, 2.0, :three, :"three"])
[1, 2, 2.0, :three]
Link to this function dedup_by(enumerable, fun) View Source
dedup_by(t(), (element() -> term())) :: list()

Enumerates the enumerable, returning a list where all consecutive duplicated elements are collapsed to a single element.

The function fun maps every element to a term which is used to determine if two elements are duplicates.

Examples

iex> Enum.dedup_by([{1, :a}, {2, :b}, {2, :c}, {1, :a}], fn {x, _} -> x end)
[{1, :a}, {2, :b}, {1, :a}]

iex> Enum.dedup_by([5, 1, 2, 3, 2, 1], fn x -> x > 2 end)
[5, 1, 3, 2]
Link to this function drop(enumerable, amount) View Source
drop(t(), integer()) :: list()

Drops the amount of items from the enumerable.

If a negative amount is given, the amount of last values will be dropped. The enumerable will be enumerated once to retrieve the proper index and the remaining calculation is performed from the end.

Examples

iex> Enum.drop([1, 2, 3], 2)
[3]

iex> Enum.drop([1, 2, 3], 10)
[]

iex> Enum.drop([1, 2, 3], 0)
[1, 2, 3]

iex> Enum.drop([1, 2, 3], -1)
[1, 2]
Link to this function drop_every(enumerable, nth) View Source
drop_every(t(), non_neg_integer()) :: list()

Returns a list of every nth item in the enumerable dropped, starting with the first element.

The first item is always dropped, unless nth is 0.

The second argument specifying every nth item must be a non-negative integer.

Examples

iex> Enum.drop_every(1..10, 2)
[2, 4, 6, 8, 10]

iex> Enum.drop_every(1..10, 0)
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

iex> Enum.drop_every([1, 2, 3], 1)
[]
Link to this function drop_while(enumerable, fun) View Source
drop_while(t(), (element() -> as_boolean(term()))) :: list()

Drops items at the beginning of the enumerable while fun returns a truthy value.

Examples

iex> Enum.drop_while([1, 2, 3, 2, 1], fn(x) -> x < 3 end)
[3, 2, 1]
Link to this function each(enumerable, fun) View Source
each(t(), (element() -> any())) :: :ok

Invokes the given fun for each item in the enumerable.

Returns :ok.

Examples

Enum.each(["some", "example"], fn(x) -> IO.puts x end)
"some"
"example"
#=> :ok
Link to this function empty?(enumerable) View Source
empty?(t()) :: boolean()

Determines if the enumerable is empty.

Returns true if enumerable is empty, otherwise false.

Examples

iex> Enum.empty?([])
true

iex> Enum.empty?([1, 2, 3])
false
Link to this function fetch(enumerable, index) View Source
fetch(t(), index()) :: {:ok, element()} | :error

Finds the element at the given index (zero-based).

Returns {:ok, element} if found, otherwise :error.

A negative index can be passed, which means the enumerable is enumerated once and the index is counted from the end (e.g. -1 fetches the last element).

Note this operation takes linear time. In order to access the element at index index, it will need to traverse index previous elements.

Examples

iex> Enum.fetch([2, 4, 6], 0)
{:ok, 2}

iex> Enum.fetch([2, 4, 6], -3)
{:ok, 2}

iex> Enum.fetch([2, 4, 6], 2)
{:ok, 6}

iex> Enum.fetch([2, 4, 6], 4)
:error
Link to this function fetch!(enumerable, index) View Source
fetch!(t(), index()) :: element() | no_return()

Finds the element at the given index (zero-based).

Raises OutOfBoundsError if the given index is outside the range of the enumerable.

Note this operation takes linear time. In order to access the element at index index, it will need to traverse index previous elements.

Examples

iex> Enum.fetch!([2, 4, 6], 0)
2

iex> Enum.fetch!([2, 4, 6], 2)
6

iex> Enum.fetch!([2, 4, 6], 4)
** (Enum.OutOfBoundsError) out of bounds error
Link to this function filter(enumerable, fun) View Source
filter(t(), (element() -> as_boolean(term()))) :: list()

Filters the enumerable, i.e. returns only those elements for which fun returns a truthy value.

See also reject/2 which discards all elements where the function returns true.

Examples

iex> Enum.filter([1, 2, 3], fn(x) -> rem(x, 2) == 0 end)
[2]

Keep in mind that filter is not capable of filtering and transforming an element at the same time. If you would like to do so, consider using flat_map/2. For example, if you want to convert all strings that represent an integer and discard the invalid one in one pass:

strings = ["1234", "abc", "12ab"]
Enum.flat_map(strings, fn string ->
  case Integer.parse(string) do
    {int, _rest} -> [int] # transform to integer
    :error -> [] # skip the value
  end
end)
Link to this function find(enumerable, default \\ nil, fun) View Source
find(t(), default(), (element() -> any())) :: element() | default()

Returns the first item for which fun returns a truthy value. If no such item is found, returns default.

Examples

iex> Enum.find([2, 4, 6], fn(x) -> rem(x, 2) == 1 end)
nil

iex> Enum.find([2, 4, 6], 0, fn(x) -> rem(x, 2) == 1 end)
0

iex> Enum.find([2, 3, 4], fn(x) -> rem(x, 2) == 1 end)
3
Link to this function find_index(enumerable, fun) View Source
find_index(t(), (element() -> any())) :: non_neg_integer() | nil

Similar to find/3, but returns the index (zero-based) of the element instead of the element itself.

Examples

iex> Enum.find_index([2, 4, 6], fn(x) -> rem(x, 2) == 1 end)
nil

iex> Enum.find_index([2, 3, 4], fn(x) -> rem(x, 2) == 1 end)
1
Link to this function find_value(enumerable, default \\ nil, fun) View Source
find_value(t(), any(), (element() -> any())) :: any() | nil

Similar to find/3, but returns the value of the function invocation instead of the element itself.

Examples

iex> Enum.find_value([2, 4, 6], fn(x) -> rem(x, 2) == 1 end)
nil

iex> Enum.find_value([2, 3, 4], fn(x) -> rem(x, 2) == 1 end)
true

iex> Enum.find_value([1, 2, 3], "no bools!", &is_boolean/1)
"no bools!"
Link to this function flat_map(enumerable, fun) View Source
flat_map(t(), (element() -> t())) :: list()

Maps the given fun over enumerable and flattens the result.

This function returns a new enumerable built by appending the result of invoking fun on each element of enumerable together; conceptually, this is similar to a combination of map/2 and concat/1.

Examples

iex> Enum.flat_map([:a, :b, :c], fn(x) -> [x, x] end)
[:a, :a, :b, :b, :c, :c]

iex> Enum.flat_map([{1, 3}, {4, 6}], fn({x, y}) -> x..y end)
[1, 2, 3, 4, 5, 6]

iex> Enum.flat_map([:a, :b, :c], fn(x) -> [[x]] end)
[[:a], [:b], [:c]]
Link to this function flat_map_reduce(enumerable, acc, fun) View Source
flat_map_reduce(t(), acc, fun) :: {[any()], any()}
when fun: (element(), acc -> {t(), acc} | {:halt, acc}), acc: any()

Maps and reduces an enumerable, flattening the given results (only one level deep).

It expects an accumulator and a function that receives each enumerable item, and must return a tuple containing a new enumerable (often a list) with the new accumulator or a tuple with :halt as first element and the accumulator as second.

Examples

iex> enumerable = 1..100
iex> n = 3
iex> Enum.flat_map_reduce(enumerable, 0, fn i, acc ->
...>   if acc < n, do: {[i], acc + 1}, else: {:halt, acc}
...> end)
{[1, 2, 3], 3}

iex> Enum.flat_map_reduce(1..5, 0, fn(i, acc) -> {[[i]], acc + i} end)
{[[1], [2], [3], [4], [5]], 15}
Link to this function group_by(enumerable, key_fun, value_fun \\ fn x -> x end) View Source
group_by(t(), (element() -> any()), (element() -> any())) :: map()

Splits the enumerable into groups based on key_fun.

The result is a map where each key is given by key_fun and each value is a list of elements given by value_fun. The order of elements within each list is preserved from the enumerable. However, like all maps, the resulting map is unordered.

Examples

iex> Enum.group_by(~w{ant buffalo cat dingo}, &String.length/1)
%{3 => ["ant", "cat"], 5 => ["dingo"], 7 => ["buffalo"]}

iex> Enum.group_by(~w{ant buffalo cat dingo}, &String.length/1, &String.first/1)
%{3 => ["a", "c"], 5 => ["d"], 7 => ["b"]}
Link to this function intersperse(enumerable, element) View Source
intersperse(t(), element()) :: list()

Intersperses element between each element of the enumeration.

Complexity: O(n).

Examples

iex> Enum.intersperse([1, 2, 3], 0)
[1, 0, 2, 0, 3]

iex> Enum.intersperse([1], 0)
[1]

iex> Enum.intersperse([], 0)
[]

Inserts the given enumerable into a collectable.

Examples

iex> Enum.into([1, 2], [0])
[0, 1, 2]

iex> Enum.into([a: 1, b: 2], %{})
%{a: 1, b: 2}

iex> Enum.into(%{a: 1}, %{b: 2})
%{a: 1, b: 2}

iex> Enum.into([a: 1, a: 2], %{})
%{a: 2}
Link to this function into(enumerable, collectable, transform) View Source
into(Enumerable.t(), Collectable.t(), (term() -> term())) :: Collectable.t()

Inserts the given enumerable into a collectable according to the transformation function.

Examples

iex> Enum.into([2, 3], [3], fn x -> x * 3 end)
[3, 6, 9]

iex> Enum.into(%{a: 1, b: 2}, %{c: 3}, fn {k, v} -> {k, v * 2} end)
%{a: 2, b: 4, c: 3}
Link to this function join(enumerable, joiner \\ "") View Source
join(t(), String.t()) :: String.t()

Joins the given enumerable into a binary using joiner as a separator.

If joiner is not passed at all, it defaults to the empty binary.

All items in the enumerable must be convertible to a binary, otherwise an error is raised.

Examples

iex> Enum.join([1, 2, 3])
"123"

iex> Enum.join([1, 2, 3], " = ")
"1 = 2 = 3"
Link to this function map(enumerable, fun) View Source
map(t(), (element() -> any())) :: list()

Returns a list where each item is the result of invoking fun on each corresponding item of enumerable.

For maps, the function expects a key-value tuple.

Examples

iex> Enum.map([1, 2, 3], fn(x) -> x * 2 end)
[2, 4, 6]

iex> Enum.map([a: 1, b: 2], fn({k, v}) -> {k, -v} end)
[a: -1, b: -2]
Link to this function map_every(enumerable, nth, fun) View Source
map_every(t(), non_neg_integer(), (element() -> any())) :: list()

Returns a list of results of invoking fun on every nth item of enumerable, starting with the first element.

The first item is always passed to the given function, unless nth is 0.

The second argument specifying every nth item must be a non-negative integer.

If nth is 0, then enumerable is directly converted to a list, without fun being ever applied.

Examples

iex> Enum.map_every(1..10, 2, fn x -> x + 1000 end)
[1001, 2, 1003, 4, 1005, 6, 1007, 8, 1009, 10]

iex> Enum.map_every(1..10, 3, fn x -> x + 1000 end)
[1001, 2, 3, 1004, 5, 6, 1007, 8, 9, 1010]

iex> Enum.map_every(1..5, 0, fn x -> x + 1000 end)
[1, 2, 3, 4, 5]

iex> Enum.map_every([1, 2, 3], 1, fn x -> x + 1000 end)
[1001, 1002, 1003]
Link to this function map_join(enumerable, joiner \\ "", mapper) View Source
map_join(t(), String.t(), (element() -> String.Chars.t())) :: String.t()

Maps and joins the given enumerable in one pass.

joiner can be either a binary or a list and the result will be of the same type as joiner. If joiner is not passed at all, it defaults to an empty binary.

All items returned from invoking the mapper must be convertible to a binary, otherwise an error is raised.

Examples

iex> Enum.map_join([1, 2, 3], &(&1 * 2))
"246"

iex> Enum.map_join([1, 2, 3], " = ", &(&1 * 2))
"2 = 4 = 6"
Link to this function map_reduce(enumerable, acc, fun) View Source
map_reduce(t(), any(), (element(), any() -> {any(), any()})) ::
  {any(), any()}

Invokes the given function to each item in the enumerable to reduce it to a single element, while keeping an accumulator.

Returns a tuple where the first element is the mapped enumerable and the second one is the final accumulator.

The function, fun, receives two arguments: the first one is the element, and the second one is the accumulator. fun must return a tuple with two elements in the form of {result, accumulator}.

For maps, the first tuple element must be a {key, value} tuple.

Examples

iex> Enum.map_reduce([1, 2, 3], 0, fn(x, acc) -> {x * 2, x + acc} end)
{[2, 4, 6], 6}
Link to this function max(enumerable, empty_fallback \\ fn -> raise(Enum.EmptyError) end) View Source
max(t(), (() -> empty_result)) :: element() | empty_result | no_return()
when empty_result: any()

Returns the maximal element in the enumerable according to Erlang’s term ordering.

If multiple elements are considered maximal, the first one that was found is returned.

Calls the provided empty_fallback function and returns its value if enumerable is empty. The default empty_fallback raises Enum.EmptyError.

Examples

iex> Enum.max([1, 2, 3])
3

iex> Enum.max([], fn -> 0 end)
0

The fact this function uses Erlang’s term ordering means that the comparison is structural and not semantic. For example:

iex> Enum.max([~D[2017-03-31], ~D[2017-04-01]])
~D[2017-03-31]

In the example above, max/1 returned March 31st instead of April 1st because the structural comparison compares the day before the year. This can be addressed by using max_by/1 and by relying on structures where the most significant digits come first. In this particular case, we can use Date.to_erl/1 to get a tuple representation with year, month and day fields:

iex> Enum.max_by([~D[2017-03-31], ~D[2017-04-01]], &Date.to_erl/1)
~D[2017-04-01]
Link to this function max_by(enumerable, fun, empty_fallback \\ fn -> raise(Enum.EmptyError) end) View Source
max_by(t(), (element() -> any()), (() -> empty_result)) ::
  element() | empty_result | no_return()
when empty_result: any()

Returns the maximal element in the enumerable as calculated by the given function.

If multiple elements are considered maximal, the first one that was found is returned.

Calls the provided empty_fallback function and returns its value if enumerable is empty. The default empty_fallback raises Enum.EmptyError.

Examples

iex> Enum.max_by(["a", "aa", "aaa"], fn(x) -> String.length(x) end)
"aaa"

iex> Enum.max_by(["a", "aa", "aaa", "b", "bbb"], &String.length/1)
"aaa"

iex> Enum.max_by([], &String.length/1, fn -> nil end)
nil
Link to this function member?(enumerable, element) View Source
member?(t(), element()) :: boolean()

Checks if element exists within the enumerable.

Membership is tested with the match (===) operator.

Examples

iex> Enum.member?(1..10, 5)
true
iex> Enum.member?(1..10, 5.0)
false

iex> Enum.member?([1.0, 2.0, 3.0], 2)
false
iex> Enum.member?([1.0, 2.0, 3.0], 2.000)
true

iex> Enum.member?([:a, :b, :c], :d)
false
Link to this function min(enumerable, empty_fallback \\ fn -> raise(Enum.EmptyError) end) View Source
min(t(), (() -> empty_result)) :: element() | empty_result | no_return()
when empty_result: any()

Returns the minimal element in the enumerable according to Erlang’s term ordering.

If multiple elements are considered minimal, the first one that was found is returned.

Calls the provided empty_fallback function and returns its value if enumerable is empty. The default empty_fallback raises Enum.EmptyError.

Examples

iex> Enum.min([1, 2, 3])
1

iex> Enum.min([], fn -> 0 end)
0

The fact this function uses Erlang’s term ordering means that the comparison is structural and not semantic. For example:

iex> Enum.min([~D[2017-03-31], ~D[2017-04-01]])
~D[2017-04-01]

In the example above, min/1 returned April 1st instead of March 31st because the structural comparison compares the day before the year. This can be addressed by using min_by/1 and by relying on structures where the most significant digits come first. In this particular case, we can use Date.to_erl/1 to get a tuple representation with year, month and day fields:

iex> Enum.min_by([~D[2017-03-31], ~D[2017-04-01]], &Date.to_erl/1)
~D[2017-03-31]
Link to this function min_by(enumerable, fun, empty_fallback \\ fn -> raise(Enum.EmptyError) end) View Source
min_by(t(), (element() -> any()), (() -> empty_result)) ::
  element() | empty_result | no_return()
when empty_result: any()

Returns the minimal element in the enumerable as calculated by the given function.

If multiple elements are considered minimal, the first one that was found is returned.

Calls the provided empty_fallback function and returns its value if enumerable is empty. The default empty_fallback raises Enum.EmptyError.

Examples

iex> Enum.min_by(["a", "aa", "aaa"], fn(x) -> String.length(x) end)
"a"

iex> Enum.min_by(["a", "aa", "aaa", "b", "bbb"], &String.length/1)
"a"

iex> Enum.min_by([], &String.length/1, fn -> nil end)
nil
Link to this function min_max(enumerable, empty_fallback \\ fn -> raise(Enum.EmptyError) end) View Source
min_max(t(), (() -> empty_result)) ::
  {element(), element()} | empty_result | no_return()
when empty_result: any()

Returns a tuple with the minimal and the maximal elements in the enumerable according to Erlang’s term ordering.

If multiple elements are considered maximal or minimal, the first one that was found is returned.

Calls the provided empty_fallback function and returns its value if enumerable is empty. The default empty_fallback raises Enum.EmptyError.

Examples

iex> Enum.min_max([2, 3, 1])
{1, 3}

iex> Enum.min_max([], fn -> {nil, nil} end)
{nil, nil}
Link to this function min_max_by(enumerable, fun, empty_fallback \\ fn -> raise(Enum.EmptyError) end) View Source
min_max_by(t(), (element() -> any()), (() -> empty_result)) ::
  {element(), element()} | empty_result | no_return()
when empty_result: any()

Returns a tuple with the minimal and the maximal elements in the enumerable as calculated by the given function.

If multiple elements are considered maximal or minimal, the first one that was found is returned.

Calls the provided empty_fallback function and returns its value if enumerable is empty. The default empty_fallback raises Enum.EmptyError.

Examples

iex> Enum.min_max_by(["aaa", "bb", "c"], fn(x) -> String.length(x) end)
{"c", "aaa"}

iex> Enum.min_max_by(["aaa", "a", "bb", "c", "ccc"], &String.length/1)
{"a", "aaa"}

iex> Enum.min_max_by([], &String.length/1, fn -> {nil, nil} end)
{nil, nil}
Link to this function random(enumerable) View Source
random(t()) :: element() | no_return()

Returns a random element of an enumerable.

Raises Enum.EmptyError if enumerable is empty.

This function uses Erlang’s :rand module to calculate the random value. Check its documentation for setting a different random algorithm or a different seed.

The implementation is based on the reservoir sampling algorithm. It assumes that the sample being returned can fit into memory; the input enumerable doesn’t have to, as it is traversed just once.

If a range is passed into the function, this function will pick a random value between the range limits, without traversing the whole range (thus executing in constant time and constant memory).

Examples

# Although not necessary, let's seed the random algorithm
iex> :rand.seed(:exsplus, {101, 102, 103})
iex> Enum.random([1, 2, 3])
2
iex> Enum.random([1, 2, 3])
1
iex> Enum.random(1..1_000)
776
Link to this function reduce(enumerable, fun) View Source
reduce(t(), (element(), any() -> any())) :: any()

Invokes fun for each element in the enumerable with the accumulator.

Raises Enum.EmptyError if enumerable is empty.

The first element of the enumerable is used as the initial value of the accumulator. Then the function is invoked with the next element and the accumulator. The result returned by the function is used as the accumulator for the next iteration, recursively. When the enumerable is done, the last accumulator is returned.

Since the first element of the enumerable is used as the initial value of the accumulator, fun will only be executed n - 1 times where n is the length of the enumerable. This function won’t call the specified function for enumerables that are one-element long.

If you wish to use another value for the accumulator, use Enum.reduce/3.

Examples

iex> Enum.reduce([1, 2, 3, 4], fn(x, acc) -> x * acc end)
24
Link to this function reduce(enumerable, acc, fun) View Source
reduce(t(), any(), (element(), any() -> any())) :: any()

Invokes fun for each element in the enumerable with the accumulator.

The initial value of the accumulator is acc. The function is invoked for each element in the enumerable with the accumulator. The result returned by the function is used as the accumulator for the next iteration. The function returns the last accumulator.

Examples

iex> Enum.reduce([1, 2, 3], 0, fn(x, acc) -> x + acc end)
6

Reduce as a building block

Reduce (sometimes called fold) is a basic building block in functional programming. Almost all of the functions in the Enum module can be implemented on top of reduce. Those functions often rely on other operations, such as Enum.reverse/1, which are optimized by the runtime.

For example, we could implement map/2 in terms of reduce/3 as follows:

def my_map(enumerable, fun) do
  enumerable
  |> Enum.reduce([], fn(x, acc) -> [fun.(x) | acc] end)
  |> Enum.reverse
end

In the example above, Enum.reduce/3 accumulates the result of each call to fun into a list in reverse order, which is correctly ordered at the end by calling Enum.reverse/1.

Implementing functions like map/2, filter/2 and others are a good exercise for understanding the power behind Enum.reduce/3. When an operation cannot be expressed by any of the functions in the Enum module, developers will most likely resort to reduce/3.

Link to this function reduce_while(enumerable, acc, fun) View Source
reduce_while(
  t(),
  any(),
  (element(), any() -> {:cont, any()} | {:halt, any()})
) :: any()

Reduces the enumerable until fun returns {:halt, term}.

The return value for fun is expected to be

  • {:cont, acc} to continue the reduction with acc as the new accumulator or
  • {:halt, acc} to halt the reduction and return acc as the return value of this function

Examples

iex> Enum.reduce_while(1..100, 0, fn i, acc ->
...>   if i < 3, do: {:cont, acc + i}, else: {:halt, acc}
...> end)
3
Link to this function reject(enumerable, fun) View Source
reject(t(), (element() -> as_boolean(term()))) :: list()

Returns elements of enumerable for which the function fun returns false or nil.

See also filter/2.

Examples

iex> Enum.reject([1, 2, 3], fn(x) -> rem(x, 2) == 0 end)
[1, 3]
Link to this function reverse(enumerable) View Source
reverse(t()) :: list()

Returns a list of elements in enumerable in reverse order.

Examples

iex> Enum.reverse([1, 2, 3])
[3, 2, 1]
Link to this function reverse(enumerable, tail) View Source
reverse(t(), t()) :: list()

Reverses the elements in enumerable, appends the tail, and returns it as a list.

This is an optimization for Enum.concat(Enum.reverse(enumerable), tail).

Examples

iex> Enum.reverse([1, 2, 3], [4, 5, 6])
[3, 2, 1, 4, 5, 6]
Link to this function reverse_slice(enumerable, start, count) View Source
reverse_slice(t(), non_neg_integer(), non_neg_integer()) :: list()

Reverses the enumerable in the range from initial position start through count elements.

If count is greater than the size of the rest of the enumerable, then this function will reverse the rest of the enumerable.

Examples

iex> Enum.reverse_slice([1, 2, 3, 4, 5, 6], 2, 4)
[1, 2, 6, 5, 4, 3]
Link to this function scan(enumerable, fun) View Source
scan(t(), (element(), any() -> any())) :: list()

Applies the given function to each element in the enumerable, storing the result in a list and passing it as the accumulator for the next computation. Uses the first element in the enumerable as the starting value.

Examples

iex> Enum.scan(1..5, &(&1 + &2))
[1, 3, 6, 10, 15]
Link to this function scan(enumerable, acc, fun) View Source
scan(t(), any(), (element(), any() -> any())) :: list()

Applies the given function to each element in the enumerable, storing the result in a list and passing it as the accumulator for the next computation. Uses the given acc as the starting value.

Examples

iex> Enum.scan(1..5, 0, &(&1 + &2))
[1, 3, 6, 10, 15]
Link to this function shuffle(enumerable) View Source
shuffle(t()) :: list()

Returns a list with the elements of enumerable shuffled.

This function uses Erlang’s :rand module to calculate the random value. Check its documentation for setting a different random algorithm or a different seed.

Examples

# Although not necessary, let's seed the random algorithm
iex> :rand.seed(:exsplus, {1, 2, 3})
iex> Enum.shuffle([1, 2, 3])
[2, 1, 3]
iex> Enum.shuffle([1, 2, 3])
[2, 3, 1]
Link to this function slice(enumerable, arg) View Source
slice(t(), Range.t()) :: list()

Returns a subset list of the given enumerable, from range.first to range.last positions.

Given enumerable, it drops elements until element position range.first, then takes elements until element position range.last (inclusive).

Positions are normalized, meaning that negative positions will be counted from the end (e.g. -1 means the last element of the enumerable). If range.last is out of bounds, then it is assigned as the position of the last element.

If the normalized range.first position is out of bounds of the given enumerable, or this one is greater than the normalized range.last position, then [] is returned.

Examples

iex> Enum.slice(1..100, 5..10)
[6, 7, 8, 9, 10, 11]

iex> Enum.slice(1..10, 5..20)
[6, 7, 8, 9, 10]

# last five elements (negative positions)
iex> Enum.slice(1..30, -5..-1)
[26, 27, 28, 29, 30]

# last five elements (mixed positive and negative positions)
iex> Enum.slice(1..30, 25..-1)
[26, 27, 28, 29, 30]

# out of bounds
iex> Enum.slice(1..10, 11..20)
[]

# range.first is greater than range.last
iex> Enum.slice(1..10, 6..5)
[]
Link to this function slice(enumerable, start, amount) View Source
slice(t(), index(), non_neg_integer()) :: list()

Returns a subset list of the given enumerable, from start position with amount of elements if available.

Given enumerable, it drops elements until element position start, then takes amount of elements until the end of the enumerable.

If start is out of bounds, it returns [].

If amount is greater than enumerable length, it returns as many elements as possible. If amount is zero, then [] is returned.

Examples

iex> Enum.slice(1..100, 5, 10)
[6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

# amount to take is greater than the number of elements
iex> Enum.slice(1..10, 5, 100)
[6, 7, 8, 9, 10]

iex> Enum.slice(1..10, 5, 0)
[]

# out of bound start position
iex> Enum.slice(1..10, 10, 5)
[]

# out of bound start position (negative)
iex> Enum.slice(1..10, -11, 5)
[]
Link to this function sort(enumerable) View Source
sort(t()) :: list()

Sorts the enumerable according to Erlang’s term ordering.

Uses the merge sort algorithm.

Examples

iex> Enum.sort([3, 2, 1])
[1, 2, 3]
Link to this function sort(enumerable, fun) View Source
sort(t(), (element(), element() -> boolean())) :: list()

Sorts the enumerable by the given function.

This function uses the merge sort algorithm. The given function should compare two arguments, and return true if the first argument precedes the second one.

Examples

iex> Enum.sort([1, 2, 3], &(&1 >= &2))
[3, 2, 1]

The sorting algorithm will be stable as long as the given function returns true for values considered equal:

iex> Enum.sort ["some", "kind", "of", "monster"], &(byte_size(&1) <= byte_size(&2))
["of", "some", "kind", "monster"]

If the function does not return true for equal values, the sorting is not stable and the order of equal terms may be shuffled. For example:

iex> Enum.sort ["some", "kind", "of", "monster"], &(byte_size(&1) < byte_size(&2))
["of", "kind", "some", "monster"]
Link to this function sort_by(enumerable, mapper, sorter \\ &<=/2) View Source
sort_by(
  t(),
  (element() -> mapped_element),
  (mapped_element, mapped_element -> boolean())
) :: list()
when mapped_element: element()

Sorts the mapped results of the enumerable according to the provided sorter function.

This function maps each element of the enumerable using the provided mapper function. The enumerable is then sorted by the mapped elements using the sorter function, which defaults to Kernel.<=/2.

sort_by/3 differs from sort/2 in that it only calculates the comparison value for each element in the enumerable once instead of once for each element in each comparison. If the same function is being called on both elements, it’s also more compact to use sort_by/3.

Examples

Using the default sorter of <=/2:

iex> Enum.sort_by(["some", "kind", "of", "monster"], &byte_size/1)
["of", "some", "kind", "monster"]

Using a custom sorter to override the order:

iex> Enum.sort_by(["some", "kind", "of", "monster"], &byte_size/1, &>=/2)
["monster", "some", "kind", "of"]

Sorting by multiple properties - first by size, then by first letter (this takes advantage of the fact that tuples are compared element-by-element):

iex> Enum.sort_by(["some", "kind", "of", "monster"], &{byte_size(&1), String.first(&1)})
["of", "kind", "some", "monster"]
Link to this function split(enumerable, count) View Source
split(t(), integer()) :: {list(), list()}

Splits the enumerable into two enumerables, leaving count elements in the first one.

If count is a negative number, it starts counting from the back to the beginning of the enumerable.

Be aware that a negative count implies the enumerable will be enumerated twice: once to calculate the position, and a second time to do the actual splitting.

Examples

iex> Enum.split([1, 2, 3], 2)
{[1, 2], [3]}

iex> Enum.split([1, 2, 3], 10)
{[1, 2, 3], []}

iex> Enum.split([1, 2, 3], 0)
{[], [1, 2, 3]}

iex> Enum.split([1, 2, 3], -1)
{[1, 2], [3]}

iex> Enum.split([1, 2, 3], -5)
{[], [1, 2, 3]}
Link to this function split_while(enumerable, fun) View Source
split_while(t(), (element() -> as_boolean(term()))) :: {list(), list()}

Splits enumerable in two at the position of the element for which fun returns false for the first time.

Examples

iex> Enum.split_while([1, 2, 3, 4], fn(x) -> x < 3 end)
{[1, 2], [3, 4]}
Link to this function split_with(enumerable, fun) View Source
split_with(t(), (element() -> any())) :: {list(), list()}

Splits the enumerable in two lists according to the given function fun.

Splits the given enumerable in two lists by calling fun with each element in the enumerable as its only argument. Returns a tuple with the first list containing all the elements in enumerable for which applying fun returned a truthy value, and a second list with all the elements for which applying fun returned a falsy value (false or nil).

The elements in both the returned lists are in the same relative order as they were in the original enumerable (if such enumerable was ordered, e.g., a list); see the examples below.

Examples

iex> Enum.split_with([5, 4, 3, 2, 1, 0], fn(x) -> rem(x, 2) == 0 end)
{[4, 2, 0], [5, 3, 1]}

iex> Enum.split_with(%{a: 1, b: -2, c: 1, d: -3}, fn({_k, v}) -> v < 0 end)
{[b: -2, d: -3], [a: 1, c: 1]}

iex> Enum.split_with(%{a: 1, b: -2, c: 1, d: -3}, fn({_k, v}) -> v > 50 end)
{[], [a: 1, b: -2, c: 1, d: -3]}

iex> Enum.split_with(%{}, fn({_k, v}) -> v > 50 end)
{[], []}
Link to this function sum(enumerable) View Source
sum(t()) :: number()

Returns the sum of all elements.

Raises ArithmeticError if enumerable contains a non-numeric value.

Examples

iex> Enum.sum([1, 2, 3])
6
Link to this function take(enumerable, amount) View Source
take(t(), integer()) :: list()

Takes the first amount items from the enumerable.

If a negative amount is given, the amount of last values will be taken. The enumerable will be enumerated once to retrieve the proper index and the remaining calculation is performed from the end.

Examples

iex> Enum.take([1, 2, 3], 2)
[1, 2]

iex> Enum.take([1, 2, 3], 10)
[1, 2, 3]

iex> Enum.take([1, 2, 3], 0)
[]

iex> Enum.take([1, 2, 3], -1)
[3]
Link to this function take_every(enumerable, nth) View Source
take_every(t(), non_neg_integer()) :: list()

Returns a list of every nth item in the enumerable, starting with the first element.

The first item is always included, unless nth is 0.

The second argument specifying every nth item must be a non-negative integer.

Examples

iex> Enum.take_every(1..10, 2)
[1, 3, 5, 7, 9]

iex> Enum.take_every(1..10, 0)
[]

iex> Enum.take_every([1, 2, 3], 1)
[1, 2, 3]
Link to this function take_random(enumerable, count) View Source
take_random(t(), non_neg_integer()) :: list()

Takes count random items from enumerable.

Notice this function will traverse the whole enumerable to get the random sublist.

See random/1 for notes on implementation and random seed.

Examples

# Although not necessary, let's seed the random algorithm
iex> :rand.seed(:exsplus, {1, 2, 3})
iex> Enum.take_random(1..10, 2)
[5, 4]
iex> Enum.take_random(?a..?z, 5)
'ipybz'
Link to this function take_while(enumerable, fun) View Source
take_while(t(), (element() -> as_boolean(term()))) :: list()

Takes the items from the beginning of the enumerable while fun returns a truthy value.

Examples

iex> Enum.take_while([1, 2, 3], fn(x) -> x < 3 end)
[1, 2]
Link to this function to_list(enumerable) View Source
to_list(t()) :: [element()]

Converts enumerable to a list.

Examples

iex> Enum.to_list(1..3)
[1, 2, 3]
Link to this function uniq(enumerable) View Source
uniq(t()) :: list()

Enumerates the enumerable, removing all duplicated elements.

Examples

iex> Enum.uniq([1, 2, 3, 3, 2, 1])
[1, 2, 3]
Link to this function uniq_by(enumerable, fun) View Source
uniq_by(t(), (element() -> term())) :: list()

Enumerates the enumerable, by removing the elements for which function fun returned duplicate items.

The function fun maps every element to a term. Two elements are considered duplicates if the return value of fun is equal for both of them.

The first occurrence of each element is kept.

Example

iex> Enum.uniq_by([{1, :x}, {2, :y}, {1, :z}], fn {x, _} -> x end)
[{1, :x}, {2, :y}]

iex> Enum.uniq_by([a: {:tea, 2}, b: {:tea, 2}, c: {:coffee, 1}], fn {_, y} -> y end)
[a: {:tea, 2}, c: {:coffee, 1}]
Link to this function unzip(enumerable) View Source
unzip(t()) :: {[element()], [element()]}

Opposite of Enum.zip/2; extracts a two-element tuples from the enumerable and groups them together.

It takes an enumerable with items being two-element tuples and returns a tuple with two lists, each of which is formed by the first and second element of each tuple, respectively.

This function fails unless enumerable is or can be converted into a list of tuples with exactly two elements in each tuple.

Examples

iex> Enum.unzip([{:a, 1}, {:b, 2}, {:c, 3}])
{[:a, :b, :c], [1, 2, 3]}

iex> Enum.unzip(%{a: 1, b: 2})
{[:a, :b], [1, 2]}
Link to this function with_index(enumerable, offset \\ 0) View Source
with_index(t(), integer()) :: [{element(), index()}]

Returns the enumerable with each element wrapped in a tuple alongside its index.

If an offset is given, we will index from the given offset instead of from zero.

Examples

iex> Enum.with_index([:a, :b, :c])
[a: 0, b: 1, c: 2]

iex> Enum.with_index([:a, :b, :c], 3)
[a: 3, b: 4, c: 5]
Link to this function zip(enumerables) View Source
zip([t()]) :: t()
zip(t()) :: t()

Zips corresponding elements from a finite collection of enumerables into one list of tuples.

The zipping finishes as soon as any enumerable in the given collection completes.

Examples

iex> Enum.zip([[1, 2, 3], [:a, :b, :c], ["foo", "bar", "baz"]])
[{1, :a, "foo"}, {2, :b, "bar"}, {3, :c, "baz"}]

iex> Enum.zip([[1, 2, 3, 4, 5], [:a, :b, :c]])
[{1, :a}, {2, :b}, {3, :c}]
Link to this function zip(enumerable1, enumerable2) View Source
zip(t(), t()) :: [{any(), any()}]

Zips corresponding elements from two enumerables into one list of tuples.

The zipping finishes as soon as any enumerable completes.

Examples

iex> Enum.zip([1, 2, 3], [:a, :b, :c])
[{1, :a}, {2, :b}, {3, :c}]

iex> Enum.zip([1, 2, 3, 4, 5], [:a, :b, :c])
[{1, :a}, {2, :b}, {3, :c}]